Parallel Circuits - Engineering

Q1:

An ammeter has an internal resistance of 50 . The meter movement itself can handle up to 1 mA. If 10 mA is applied to the meter, the shunt resistor, RSH1, is approximately

A 55 

B 5.5 

C 50 

D

ANS:B - 5.5 

Both current and resistance is known for 50 ohms.

Hence;
Voltage = 50 x 1 mA = 0.05.
Voltage is same in parallel.

Hence for unkown resistor
R= V/I.
R= 0.05/9 mA = 5.5 ohm.