Q1: An antisymmetric filter having odd number of coefficient may have a performance as

ANS:D - all pass

Consider an anti-symmetric filter response with order 5. h(n) = [h(2), h(1), h(0), - h(1), - h(2)] We know, H(0) = addition of all component values. Hence H(0) = h(0) Similarly H(p) = addition of all component values with alternate negative sign. = h(2) - h(1) + h(0) + h(1) - h(2) = h(0) Hence we get all pass filter.