An electron in a metal suffers collision and if the probability of it being scattered over an angle dθ is 2p P(θ) sin θ dθ where P(θ) is an arbitrary function of scattering angle θ, then-A-2pP(θ) sin θ dθ = 0B-2pP(θ) sin θ dθ = 2C-2pP(θ) sin θ dθ = 1D-2pP(θ) sin θ dθ = 1-C-2pP(θ) sin θ dθ = 1

Question

An electron in a metal suffers collision and if the probability of it being scattered over an angle d&theta; is 2p P(&theta;) sin &theta; d&theta; where P(&theta;) is an arbitrary function of scattering angle &theta;, then-A-2pP(θ) sin θ dθ = 0B-2pP(θ) sin θ dθ = 2C-2pP(θ) sin θ dθ = 1D-2pP(θ) sin θ dθ = 1-C-2pP(θ) sin θ dθ = 1

APTITUDE CRACK · Accepted Answer

The correct option is  C 2pP(θ) sin θ dθ = 1 No answer description is available.

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Q1: An electron in a metal suffers collision and if the probability of it being scattered over an angle dθ is 2p P(θ) sin θ dθ where P(θ) is an arbitrary function of scattering angle θ, then

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Q1: An electron in a metal suffers collision and if the probability of it being scattered over an angle dθ is 2p P(θ) sin θ dθ where P(θ) is an arbitrary function of scattering angle θ, then

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