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Enzymes and Kinetics

Q1:

An enzyme is assayed at an initial substrate concentration of 2 x 10-5M. In 6 minute, half of the substrate is used. The Km for the substrate is 2 x 10-3M. The value of k in minute is

A 0.115

B 0.42

C 0.093

D 6.693

ANS:A - 0.115

Solution to this question:

Tthe enzymatic reaction is mainly first order reaction.

From the first order of reaction, k = 0.693/half time (t1/2).

Half time is 6 min as given in the question.

So, 0.693/6 = 0.1155.



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