An enzyme is assayed at an initial substrate concentration of 2 x 10-5M. In 6 minute, half of the substrate is used. The Km for the substrate is 2 x 10-3M. The value of k in minute is-A-0.115B-0.42C-0.093D-6.693-A-0.115

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A 0.115 Solution to this question: Tthe enzymatic reaction is mainly first order reaction. From the first order of reaction, k = 0.693/half time (t1/2). Half time is 6 min as given in the question. So, 0.693/6 = 0.1155.

Enzymes and Kinetics - Medical Science

An enzyme is assayed at an initial substrate concentration of 2 x 10^-5M. In 6 minute, half of the substrate is used. The K_m for the substrate is 2 x 10^-3M. The value of k in minute is

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Enzymes and Kinetics - Medical Science

An enzyme is assayed at an initial substrate concentration of 2 x 10-5M. In 6 minute, half of the substrate is used. The Km for the substrate is 2 x 10-3M. The value of k in minute is

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An enzyme is assayed at an initial substrate concentration of 2 x 10^-5M. In 6 minute, half of the substrate is used. The K_m for the substrate is 2 x 10^-3M. The value of k in minute is

For help Students Orientation
Mcqs Questions