RCC Structures Design - Engineering

Q1:

An intermediate T-beam reinforced with two layers of tensile steel with clear cover 13 cm encasted with the floor of a hall 12 metres by 7 metres, is spaced at 3 metres from adjoining beams and if the width of the beam is 20 cm, the breadth of the flange is

A 300 cm

B 233 cm

C 176 cm

D 236 cm

E 255 cm

ANS:C - 176 cm

To find the breadth of the flange of the T-beam, we first need to calculate the clear span of the T-beam between the supporting beams. Then, we can determine the effective width of the flange based on the dimensions provided. Given:

  • Clear cover: 13 cm
  • Hall dimensions: 12 meters by 7 meters
  • Spacing between adjoining beams: 3 meters
  • Width of the T-beam: 20 cm
First, let's calculate the clear span of the T-beam between the supporting beams: The clear span of the T-beam will be equal to the distance between the two adjoining beams minus the clear cover on both sides. Clear span = Distance between beams - 2 * Clear cover The distance between the beams along the length of the hall is given by the hall width minus the spacing between the beams: Distance between beams = Hall width - Spacing between beams = 7 meters - 3 meters = 4 meters Now, let's calculate the clear span: Clear span = 4 meters - 2 * 13 cm = 4 meters - 26 cm = 4 meters - 0.26 meters = 3.74 meters Next, we can determine the effective width of the flange: Effective width of the flange = Width of T-beam - Clear cover on one side Effective width of the flange = 20 cm - 13 cm = 7 cm However, it seems there might be a mistake in the options provided. The calculated effective width of the flange is 7 cm, not in the range of the given options. It's possible that there might be a discrepancy in the question or the calculations. Please double-check the problem or provide additional information if needed.