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Ohm''s Law - Engineering

Q1:

Approximately how many milliamperes of current flow through a circuit with a 40 V source and 6.8 k of resistance?

A 27.2 mA

B 59 mA

C 5.9 mA

D 590 mA

ANS:C - 5.9 mA

I = ?
V = 40V
R = 6.8 K Ohm
R = 6800 Ohm.

Since
I = V/R
I = 40/6800,
I = 0.00588,
I = 0.00588 (10^3)(10^-3)
I = 5.9 mA.