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Applied Mechanics - Engineering

Q1:

Ball A of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/s hits an identical stationary ball B on the table. If the impact is perfectly elastic, the velocity of the ball B just after impact would be

A zero

B 5 m/sec

C 10 m/sec

D none of these.

ANS:C - 10 m/sec

Law of conservation:

Initial of ball = final of ball.
m1u1 + m2u2 = m1v1 + m2v2.
250x10 + 250x0 = 250x0 + 250x v2,
v2 = 10 m/sc.