Q1: Calculate the magnitude of the impedance in the given circuit.

ANS:C - 26.1 M

Impedence Z=square root(R^2+Xc^2)
Xc=1/(2*pi*f*c)=1/(2*3.14*20*10^3*0.33*10^-12)
=1/(6.28*20*0.33)*(10^3-12)
=(1/41.448)*10^9
=0.0241*10^9
Xc=24.12*10^6=24.12Mohm
Z=Square root(R^2+Xc^2)
=Square root[(10*10^6)^2+(24.12*10^6)^2]
=Square root[(10)^2+(24.12)^2*(10^6)^2]
=Square root[100+582.0928*(10^6)^2]
=Square root[682.0928*(10^6)^2]
=26.11*10^6=26.1Mohm