Consider the following BJT circuit:hie = 2 k ohmhfe = 100hre = 2.5 x 10-4The value of Ri is :-A-2.46 kΩB-2.88 kΩC-200 ΩD-18.48 Ω-A-2.46 kΩ

A 2.46 kΩ Ri = 7 || 4.3 || (2 + (1 + 100)330) = 2.88 kΩ.