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Digital Electronics - Engineering

Q1:

Decimal number 46 in excess 3 code =

A 1000 1001

B 0111 1001

C 0111 1111

D 1000 1111

ANS:B - 0111 1001

Decimal 46 in excess 3 code = 46 + 33 = 79 in decimal = 0111 1001 in 4 bit binary.