Stoichiometry

Q1: Degrees of freedom will be equal to the number of components for a system comprising of

A only soluble liquid components.

B partially miscible two liquid components system having two phases.

C two liquid components and one solute (soluble in both the liquids).

D none of these.

ANS:A - only soluble liquid components.

The degrees of freedom for a system depend on the number of components and the number of phases present. For a system comprising only soluble liquid components, the degrees of freedom will be equal to the number of components minus one. This is because in a single-phase system of soluble liquids, there is only one phase, and there is a constraint imposed by the requirement that the overall composition must sum to 1 (total concentration). Therefore, one degree of freedom is lost. For a partially miscible system consisting of two liquid components with two phases, the degrees of freedom will be equal to the number of components minus the number of phases plus two. This is because there are two phases present, and there are additional constraints imposed by the phase equilibrium conditions. For a system consisting of two liquid components and one solute soluble in both liquids, the degrees of freedom will be determined by the number of components and the number of phases, similar to the partially miscible system scenario. So, in summary:

  • For a system of only soluble liquid components, the degrees of freedom will be equal to the number of components minus one.
  • For a partially miscible system with two liquid components and two phases, the degrees of freedom will be equal to the number of components minus the number of phases plus two.
  • For a system with two liquid components and one solute soluble in both liquids, the degrees of freedom will depend on the specific conditions of the system but will generally be determined by the number of components and phases present.
Therefore, the correct option is: none of these.



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