Q1: Diffusion is that property by virtue of which a perfume bottle when opened up in a room, makes the whole room fragrant with its smell. If a perfume 'X' diffuses twice as fast as another perfume 'Y'; what is the molecular weight of 'Y', if the vapor density of gas 'X' is 2 ? Molecular weight of gas 'X' is to be assumed to be 2.

ANS:D - 16

To solve this problem, we can use Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molecular weight. Mathematically, Graham's law can be expressed as: Rate of diffusion∝1Molecular weightRate of diffusion∝Molecular weight​1​ Given that perfume 'X' diffuses twice as fast as perfume 'Y', we can set up the following relationship: Rate of diffusion of XRate of diffusion of Y=Molecular weight of YMolecular weight of XRate of diffusion of YRate of diffusion of X​=Molecular weight of X​Molecular weight of Y​​ Given that the molecular weight of gas 'X' is 2 and the vapor density of gas 'X' is also 2 (since vapor density is the density of the gas relative to hydrogen, and the molecular weight of hydrogen is approximately 2), we can substitute these values into the equation: 21=Molecular weight of Y212​=2​Molecular weight of Y​​ Solving for the molecular weight of Y: Molecular weight of Y=2×2Molecular weight of Y​=2×2​