Stoichiometry - Engineering
Q1: Diffusion is that property by virtue of which a perfume bottle when opened up in a room, makes the whole room fragrant with its smell. If a perfume 'X' diffuses twice as fast as another perfume 'Y'; what is the molecular weight of 'Y', if the vapor density of gas 'X' is 2 ? Molecular weight of gas 'X' is to be assumed to be 2.A 2
B 4
C 8
D 16
ANS:D - 16 To solve this problem, we can use Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molecular weight. Mathematically, Graham's law can be expressed as: Rate of diffusion∝1Molecular weightRate of diffusion∝Molecular weight1 Given that perfume 'X' diffuses twice as fast as perfume 'Y', we can set up the following relationship: Rate of diffusion of XRate of diffusion of Y=Molecular weight of YMolecular weight of XRate of diffusion of YRate of diffusion of X=Molecular weight of XMolecular weight of Y Given that the molecular weight of gas 'X' is 2 and the vapor density of gas 'X' is also 2 (since vapor density is the density of the gas relative to hydrogen, and the molecular weight of hydrogen is approximately 2), we can substitute these values into the equation: 21=Molecular weight of Y212=2Molecular weight of Y Solving for the molecular weight of Y: Molecular weight of Y=2×2Molecular weight of Y=2×2 |
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