ANS:A - increases

When the diameter of a droplet decreases, the inside pressure intensity generally increases. This phenomenon can be understood through the Laplace pressure equation, which describes the relationship between surface tension, pressure difference, and curvature of a droplet or bubble. The Laplace pressure (Pl​) can be expressed as: PL​=2γ/r​ Where:

• γ is the surface tension of the liquid,
• r is the radius of curvature of the droplet or bubble.

From the equation, we observe that as the radius of curvature decreases (such as when the diameter of the droplet decreases), the Laplace pressure increases. This implies that the pressure inside the droplet must increase to counteract the increased surface tension and maintain equilibrium. Therefore, when the diameter of a droplet decreases, the inside pressure intensity generally increases.