Problems on Numbers

Q1: Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

A 3

B 10

C 17

D 20

ANS:A - 3

Let the number be x.

Then, x + 17 =	60
	x

x² + 17x - 60 = 0

(x + 20)(x - 3) = 0

x = 3.

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