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Q1:

Find the maximum power that can be delivered to a load

A 0.025 W

B 2.5 W

C 2.5 W

D 0.25 W

ANS:D - 0.25 W

PL = I2R = x R •••(i) where zS = 100 + j50 zL = 100 - j50 Putting the values in eq. (i) PL =X l00 = 0.25 watts.



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