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Circuit Theorems and Conversions - Engineering

Q1:

Find the Norton circuit, that is, IIN and RN, for the circuit given below.

A 478 mA, 12.8 

B 750 mA, 12.8 

C 478 mA, 6.8 

D 750 mA, 6.8 

ANS:A - 478 mA, 12.8 

12*12/12+12=6 ohm.
6+6.8=12.8 ohm.
V-12/12+v/12 = 6v.
6/12.8= 468 mA.