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Q1:

Find the power absorbed or delivered by each source:

A a = -32 b = - 12 c = -80 d = -60

B a = -32 b = - 12 c = 80 d = 60

C a = 32 b = 12 c = -80 d = 60

D a = -32 b = 12 c = 80 d = -60

ANS:D - a = -32 b = 12 c = 80 d = -60

Source a : Power : 8 x (4) = - 32 W. Source A has delivered the power as it is. - ve. Source b: Source B has absorbed power of + 12 W as power is positive Source c: Source C has absorbed power of 5 x 16 = 80 W Source d: Delivers power of 3 x ix x (5) = 3 x 4 x (- 5) = -60 W Total power of the network is - 32 + 12 + 80 - 60 = 0 Watts.



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