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Parallel Circuits - Engineering

Q1:

Five light bulbs are connected in parallel across 110 V. Each bulb is rated at 200 W. The current through each bulb is approximately

A 2.2 A

B 137 mA

C 1.8 A

D 9.09 A

ANS:C - 1.8 A

I = P/V= 200/110 = 1.8181 for each bulb,
Assuming the power supply is well-regulated - doesn't sag under load, the total is
1.8181 * 5 = 9.09A for the total current.