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Surveying - Engineering

Q1:

For a curve of radius 100 m and normal chord 10 m, the Rankine's deflection angle, is

A 0°25'.95

B 0°35'.95

C 1°25'.53

D 1°35'.95

E 2°51'.53.

ANS:E - 2°51'.53.

Use the formula c/2R ×180/π degrees.

Answer in decimal form 2.864°.

2° + 0.864×60minutes.
2° 51.84minutes.
2° 51 minutes .84×60seconds.
2° 51minutes 53 seconds.
2°51'53''. The ranking deflection angle = (180 x L) / 2*πR.
= 180x10 / 2x3.14x100.
= 1800/628 = 2.866.
Convert 2.866 in to degree = 2degree 51mintues 58 seconds. Rankines Deflection Angle=C/2R radian.
= 10/(2*100).
= 0.05 rad,
= (180*0.05)/π ,
= 2.86°. in Radian = C/2R.
in Degree = (C/2R)*(180/π).
in Minutes = (C/2R)*(180/π) * 60.

So, we need the answer in degree, = (C/2R)*(180/π).
= (10/200) * 57.273,
= 2.863 decimal,
= 2°51'.53. Formula is c/2R=10/2*100=1/20rad.=1/20*(180/3.14) degrees=2 degree 51 minutes and 53 seconds.