For a MOD-12 counter, the FF has a tpd = 60 ns The NAND gate has a tpd of 25 n sec. The clock frequency is-A-3.774 MHzB-> 3.774 MHzC-< 3.774 MHzD-4.167 MHz-A-3.774 MHz

Question

For a MOD-12 counter, the FF has a tpd = 60 ns The NAND gate has a tpd of 25 n sec. The clock frequency is-A-3.774 MHzB-&gt; 3.774 MHzC-&lt; 3.774 MHzD-4.167 MHz-A-3.774 MHz

APTITUDE CRACK · Accepted Answer

The correct option is  A 3.774 MHz  For a proper working, the clock period should be equal to or greater than tpd = Mod 12 4FFs = 4 x 60 = 240 nsec. Total tpd = 240 + 25 = 265 nsec. = fc and fc = 3.774 MHz.

Digital Electronics

Q1: For a MOD-12 counter, the FF has a t_pd = 60 ns The NAND gate has a t_pd of 25 n sec. The clock frequency is

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Digital Electronics

Q1: For a MOD-12 counter, the FF has a tpd = 60 ns The NAND gate has a tpd of 25 n sec. The clock frequency is

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For help Students Orientation Mcqs Questions

Q1: For a MOD-12 counter, the FF has a t_pd = 60 ns The NAND gate has a t_pd of 25 n sec. The clock frequency is

For help Students Orientation
Mcqs Questions