For a npn BJT transistor fβ is 1.64 x 108 Hz. Cμ = 10-14 F; Cp = 4 x 10-13 F and DC current gain is 90. Find fT and gm (fβ = cut off frequency, Cμ = capacitance, Cp = parasitic capacitance, gm = transconductance, fT = gain BW product)-A-fT = 1.47 x 1010 Hz ; gm = 38 milli mhoB-fT = 1.64 x 108 Hz ; gm = 30 milli mhoC-fT = 1.47 x 109 Hz ; gm = 38 mhoD-fT = 1.33 x 1012 Hz; gm = 0.37 m mh-A-fT = 1.47 x 1010 Hz ; gm = 38 milli mho

Question

For a npn BJT transistor f&beta; is 1.64 x 108 Hz. C&mu; = 10-14 F; Cp = 4 x 10-13 F and DC current gain is 90. Find fT and gm (f&beta; = cut off frequency, C&mu; = capacitance, Cp = parasitic capacitance, gm = transconductance, fT = gain BW product)-A-fT = 1.47 x 1010 Hz ; gm = 38 milli mhoB-fT = 1.64 x 108 Hz ; gm = 30 milli mhoC-fT = 1.47 x 109 Hz ; gm = 38 mhoD-fT = 1.33 x 1012 Hz; gm = 0.37 m mh-A-fT = 1.47 x 1010 Hz ; gm = 38 milli mho

APTITUDE CRACK · Accepted Answer

A fT = 1.47 x 1010 Hz ; gm = 38 milli mho  ∴ fT = 90 x 1.64 x 108 = 1.47 x 1010 Hz gm = 2pfT(Cμ + Cp) = 2 x p x 1.47 x 1010 = (10 14 + 4 x 10 13) gm= 38 mμ.

Exam Questions Papers - Engineering

For a npn BJT transistor f_β is 1.64 x 10⁸ Hz. C_μ = 10^-14 F; C_p = 4 x 10^-13 F and DC current gain is 90. Find f_T and g_m (f_β = cut off frequency, C_μ = capacitance, C_p = parasitic capacitance, g_m = transconductance, f_T = gain BW product)

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Exam Questions Papers - Engineering

For a npn BJT transistor fβ is 1.64 x 108 Hz. Cμ = 10-14 F; Cp = 4 x 10-13 F and DC current gain is 90. Find fT and gm (fβ = cut off frequency, Cμ = capacitance, Cp = parasitic capacitance, gm = transconductance, fT = gain BW product)

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For a npn BJT transistor f_β is 1.64 x 10⁸ Hz. C_μ = 10^-14 F; C_p = 4 x 10^-13 F and DC current gain is 90. Find f_T and g_m (f_β = cut off frequency, C_μ = capacitance, C_p = parasitic capacitance, g_m = transconductance, f_T = gain BW product)

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