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UPSC Civil Service Exam Questions - Engineering

Q1:

For a sleeper density of (n + 5), the number of sleepers required for constructing a broad gauge (BG) railway track of length 650 m is

A 975

B 918

C 900

D 880

ANS:C - 900

Sleeper density = (n+5).
Length of one rail for broad gauge track 12.8 say 13(I,e n),
Sleeper density=13+5=18,
The Number of sleepers required for 650m lenth=(18/13)* 650.
=899.999 say 900.