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UPSC Civil Service Exam Questions

Q1:

For a symmetrical continuous beam as shown in the figure given above, which one of the following is correct in respect of distribution factors at B ?

A δBA : δBC = 3:4

B δBA : δBC = 1:2

C δBA : δBC = 3:2

D δBA : δBC = 3:8

ANS:A - δBA : δBC = 3:4

stiffness for end A.

=3EI/L.

for end C.

=4EI/L.

So,
Distribution factor df=stifness/sum of stiffness.
3/2+4a and 4/7.
The ratio would be 3:4.



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