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Analog Electronics - Engineering

Q1:

For a transistor if adc = 0.98 and emitter current IE is 2 mA, then base current will be

A 10 μA

B 40 μA

C 80 μA

D 200 μA

ANS:A - 10 μA

ie = (b+1)ib.
a = 0.98.

b = a/1-a = 49.
b+1 = 50.
ib = 2/50 = 0.04 ma = 40 ua.