Soil Mechanics and Foundation Engineering

Q1: For determing the specific gravity of soil solids, using a pycnometer of 500 cc., the following data is available : Weight of dry empty pycnometer = 125 g Weight of dried soil and pycnometer = 500 g Weight of dried soil and distilled = 850 g water filled in pycnometer up to top The specific gravity of soil soilds, is

A 2.0

B 2.25

C 2.50

D 2.75

ANS:C - 2.50

Weight of soil solids = 500-125 = 375g.
The weight of water when the soil is also present in the pycnometer = 850-500 = 350g.
the Weight of water when water fills pycnometer = 500cc * 1g/cc = 500g (Since the unit weight of water is 1g/cc).
Therefore weight of equal volume of water = 500-350 = 150g.
Specific gravity = (Weight of soil solids)/(Weight of equal volume of water) = 375/150 = 2.5. SG = Wt of dry soil/Distilled water.

Wt of dry soil = 500 - 125,
Wt of distilled water = 850 - 500,
(no need to find W4, the density of pure water or anything else). W1= Wt. of pycnometer = 125 g.
W2 = Wt. of pycnometer + Wt. of dry soil = 500 g.
W3 = Wt. of pycnometer + wt. of dry soil + wt. of water = 850 g.
W4 = Wt. of pycnometer + wt. of water = 500*1 + 125 = 625g,
where density of pure water = 1g/cc, volume of pycnometer = 500 cc.
G = (Wt. of dry soil)/(Wt. of water of equal volume (means equal to the volume of dry soil).
G = (W2-W1)/((W4-W1)-(W3-W2)).
Hence, G = (500-125)/((625-125)-(850-500)).
G = 375/(500-350).
G = 375/150.
G = 2.5. W1 = 125.
W2 = 500.
W3 = 850.

W4 = 500*1+125 = 625.
Md = 375.

W4 = W3-Md+Md/G.
G = 2.5.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.