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Hydraulics - Engineering

Q1:

For exerting a pressure of 4.8 kg/cm2, the depth of oil (specific gravity 0.8), should be

A 40 cm

B 41 cm

C 56 cm

D 60 cm

E 76 cm

ANS:D - 60 cm

To achieve a pressure of 4.8 kg/cm², we can use the hydrostatic pressure formula: P=ρ×g×h Where:

  • P is the pressure exerted (in kg/cm²),
  • ρ is the density of the fluid (in kg/m³),
  • g is the acceleration due to gravity (in m/s²),
  • ℎ is the depth of the fluid (in meters).
Given:
  • Pressure, P=4.8 kg/cm²,
  • Specific gravity of oil, SG=0.8SG=0.8.
First, we need to find the density of the oil (ρ). Since density is the ratio of the specific gravity of the fluid to the density of water (pwater=1000ρwater​),we have: p=SG×Pwater  ​ p=0.8×1000