For the circuit shown in the figure, the capacitor C is initially uncharged. At t = 0, the switch S is closed. The voltage V_c across the capacitor at t = 1 millisecond is (In the figure shown above, the op-amp is supplied with ± 15 V and the ground has been shown by the symbol)

ANS:D - 10 volts

If we use Vc as 10 and find out the value of Vo becomes 20v which is more than the supplied voltage.

Due to this, the output becomes saturated and the virtual short circuit becomes invalid. That's why, the transition method should be used and the answer ll be none of the above (Vc= 8.94).

So, here; All options are incorrect.