For the irreversible reaction, Ca+ 2C = Ca C2 , Δ H°298 = - 60000 J . mole-1 . If a system initially containing 2 moles of calcium, 3 moles of carbon and 1 mole of calcium carbide is allowed to react to completion, the heat evolved at 298 K will be-A-30000 JB-60000 JC-90000 JD-240000 J-C-90000 J

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For the irreversible reaction, Ca+ 2C = Ca C2 , &Delta; H&deg;298 = - 60000 J . mole-1 . If a system initially containing 2 moles of calcium, 3 moles of carbon and 1 mole of calcium carbide is allowed to react to completion, the heat evolved at 298 K will be-A-30000 JB-60000 JC-90000 JD-240000 J-C-90000 J

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C 90000 J No answer description is available.

Chemical Engineering Basics

For the irreversible reaction, C_a+ 2C = C_a C₂ , Δ H°298 = - 60000 J . mole^-1 . If a system initially containing 2 moles of calcium, 3 moles of carbon and 1 mole of calcium carbide is allowed to react to completion, the heat evolved at 298 K will be

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Chemical Engineering Basics

For the irreversible reaction, Ca+ 2C = Ca C2 , Δ H°298 = - 60000 J . mole-1 . If a system initially containing 2 moles of calcium, 3 moles of carbon and 1 mole of calcium carbide is allowed to react to completion, the heat evolved at 298 K will be

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For the irreversible reaction, C_a+ 2C = C_a C₂ , Δ H°298 = - 60000 J . mole^-1 . If a system initially containing 2 moles of calcium, 3 moles of carbon and 1 mole of calcium carbide is allowed to react to completion, the heat evolved at 298 K will be

For help Students Orientation
Mcqs Questions