Exam Questions Papers - Engineering

Q1:

For the network shown below, if VD = 12 V and VGSQ = - 2 V value of RS will be

A 13.35 kΩ

B 3.35 kΩ

C 33.31 kΩ

D 3.95 kΩ

ANS:B - 3.35 kΩ

VGS = VG - IDRS - 2 = 5.44 - 2.22 X 10-3 X RS RS = 3.35 KΩ.