For the output F to be 1 in the logic circuit shown, the input combination should be-A-A = 1, B = 1, C = 0B-A = 1, B = 0, C = 0C-A = 0, B = 1, C = 0D-A = 0, B = 0, C = 1-D-A = 0, B = 0, C = 1

D A = 0, B = 0, C = 1 B = A F = A⊙B⊙C = A⊙A⊙C so, F = 1 when C = 1.