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Height and Distance

Q1: From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

A 149 m

B 156 m

C 173 m

D 200 m

ANS:C - 173 m

Let AB be the tower. Then, APB = 30° and AB = 100 m.

AB = tan 30° = 1
AP 3
 AP = (AB x 3) m
  = 1003 m
  = (100 x 1.73) m
  = 173 m.



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