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Q1:

Given (224)r = The value of the radix 'r' is :

A 5

B 6

C 7

D 10

ANS:A - 5

(224)r = = (13)r x (13)r ∴ 2r2 + 2r + 4 = (r + 3) (r + 3) = r2 + 6r + 9 ∴ r2 - 4r - 5 = 0 ∴ (r - 5) (r + 1) = 0 r = - 1 or r = 5 Negative base is not possible. Therefore base of the equation is 5.



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