- Heat Transfer - Section 1
- Heat Transfer - Section 2
- Heat Transfer - Section 3
- Heat Transfer - Section 4
- Heat Transfer - Section 5
- Heat Transfer - Section 6
- Heat Transfer - Section 7
- Heat Transfer - Section 8
- Heat Transfer - Section 9
- Heat Transfer - Section 10
- Heat Transfer - Section 11


Heat Transfer - Engineering
Q1: Hot water (0.01 m3 /min) enters the tube side of a counter current shell and tube heat exchanger at 80°C and leaves at 50°C. Cold oil (0.05 m3/min) of density 800 kg/m3 and specific heat of 2 kJ/kg.K enters at 20°C. The log mean temperature difference in °C is approximatelyA 32
B 37
C 45
D 50
ANS:A - 32 To calculate the log mean temperature difference (LMTD) for a counter-current heat exchanger, we can use the formula: LMTD=Δ�1−Δ�2ln(Δ�1/Δ�2)LMTD=ln(ΔT1/ΔT2)ΔT1−ΔT2 Where:
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