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Numbers - General Aptitude

Q1:

How many 3 digit numbers are divisible by 6 in all ?

A 149

B 150

C 151

D 166

ANS:B - 150

Required numbers are 102, 108, 114, ... , 996 This is an A.P. in which a = 102, d = 6 and l = 996 Let the number of terms be n. Then, a + (n - 1)d = 996    102 + (n - 1) x 6 = 996    6 x (n - 1) = 894    (n - 1) = 149    n = 150.