[Solved] How many bytes of memory will the following code reserve? #include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(256 * 256); if(p == NULL) printf('Allocation failed'); return 0; } - Programming - C Programming - Memory Allocation

Memory Allocation

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Q1: How many bytes of memory will the following code reserve?

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int *p;
    p = (int *)malloc(256 * 256);
    if(p == NULL)
        printf('Allocation failed');
    return 0;
}

A 65536

B Allocation failed

C Error

D No output

ANS:A - 65536

Hence 256*256 = 65536 is passed to malloc() function which can allocate upto 65535. So the memory allocation will be failed in 16 bit platform (Turbo C in DOS). If you compile the same program in 32 bit platform like Linux (GCC Compiler) it may allocate the required memory.

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Memory Allocation

Q1: How many bytes of memory will the following code reserve?
`#include<stdio.h> #include<stdlib.h> int main() { int p; p = (int )malloc(256 * 256); if(p == NULL) printf('Allocation failed'); return 0; }`

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Memory Allocation

Q1: How many bytes of memory will the following code reserve? #include<stdio.h> #include<stdlib.h> int main() { int *p; p = (int *)malloc(256 * 256); if(p == NULL) printf('Allocation failed'); return 0; }

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Q1: How many bytes of memory will the following code reserve?
`#include<stdio.h> #include<stdlib.h> int main() { int p; p = (int )malloc(256 * 256); if(p == NULL) printf('Allocation failed'); return 0; }`

For help Students Orientation
Mcqs Questions