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Electronic Devices and Circuits

Q1: If 100 V is the peak voltage across the secondary of the transformer in a half-wave rectifier (without any filter circuit), then the maximum voltage on the reverse-biased diode is

A 200 V

B 141.4 V

C 100 V

D 86 V

ANS:B - 141.4 V

The output voltage across the secondary transformer is 100Vrms.

To get the average output voltage of the diode we need to use this formula(Vm=2*Vrms/)-->Vm=2*100 = 200V.

The voltage across the diode is 200V, assuming it is an ideal diode. So the PIV should also be equal to 200V. The answer should option A.



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