Download Aptitude Crack
img not found img not found

Diodes and Applications

Q1:

If a 169.7 V half-wave peak has an average voltage of 54 V, what is the average of two full-wave peaks?

A 119.9 V

B 108.0 V

C 115.7 V

D 339.4 V

ANS:B - 108.0 V

Here half wave rectification is:

Vdc = 0.318*V(peak).

e.g: 169.7*0.318 = 53.914 = 54(approx).

And for full wave rectification:

Vdc = 0.636*V(peak).

So,
Vdc = 0.636*169.7 = 107.9292 = 108V(approx).



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.