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Series Circuits

Q1: If a 3.9 komega.gif, a 7.5 komega.gif, and a 5.6 komega.gif resistor are connected in series with a 34 V source, the voltage dropped across the 7.5 komega.gif resistor equals _____.

A 34 V

B 15 V

C 7.8 V

D 11.2 V

ANS:B - 15 V

R(Total) = (3.9 k Ω + 7.5 k Ω + 5.6 k Ω) = 17 kΩ
V = 34 V.

Then, I = V/R = 34 / 17 k Ω = 2 m A.
Now, I = 2 m A & R = 7.5 kΩ
V = I*R = 2 m A * 7.5 kΩ = 15 V.



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