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UPSC Civil Service Exam Questions - Engineering

Q1:

If a soil sample of weight 0.18 kg having a volume of 10-4 m3 and dry unit wt. of 1600 kg/m3 is mixed with 0.02 kg of water then the water content in the sample will be

A 30%

B 25%

C 20%

D 15%

ANS:B - 25%

In qstn there is W_samlpe and V_sample so that we can find Yb.
So,
Yb = 0.18/10^-4.
= 1800 kg/m^3 ..and there adding water that is 0.02 kg so (0.02/10^-4)=200.
Yb =1800+200=2000 kg/m^3,
From the formula of;
Yd =Yb/(1+w),
1600=2000/(1+w),
w= 0.25,
= 25%.