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Strings

Q1: If char=1, int=4, and float=4 bytes size, What will be the output of the program ? 
#include<stdio.h>

int main()
{
    char ch = 'A';
    printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f));
    return 0;
}

A 1, 2, 4

B 1, 4, 4

C 2, 2, 4

D 2, 4, 8

ANS:B - 1, 4, 4

Step 1: char ch = 'A'; The variable ch is declared as an character type and initialized with value 'A'. Step 2: printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14)); The sizeof function returns the size of the given expression. sizeof(ch) becomes sizeof(char). The size of char is 1 byte. sizeof('A') becomes sizeof(65). The size of int is 4 bytes (as mentioned in the question). sizeof(3.14f). The size of float is 4 bytes. Hence the output of the program is 1, 4, 4



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