Q1: If D is the diameter of a pipe of length L and f is the coefficient of friction of pipe then diameter of the nozzle d is

ANS:A -

For maximum transmission, H=3h,
where H=Total Supply Head,
h=head lost due to friction,
H=3h.

=>v^2/2g=3 flV^2/(2gD),
where, v=velocity at the nozzle end,

V=velocity in pipe.
=>Q^2/(a^2.2g)=3flQ^2/(A^2/2gD).

where a=nozzle area,

A=area of pipe,
=>3fld^4=D^5.
=>d= (D^5/(3fl))^(1/4).