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Q1: If F is the pull applied at the ends of tape in kg, l is the length of tape between end marks in metres, w is the weight of the tape in kg per metre run, then sag correction

A

B

C

D .

ANS:A -

We know ,
c = l/24 * W^2/P^2.

but total weight of tape is "W".
So W = wl.

put this value in equation, we get,
c = (l^3*w^2)/(24*p^2).



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