If for a silicon n-p-n transistor, the base to emitter voltage (VBE) is 0.7 V and the collector to base voltage VCB is 0.2 Volt, then the transistor is operating in the-A-normal active modeB-saturation modeC-inverse active modeD-cut off mode-A-normal active mode

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A normal active mode Transistor will operate in active mode because VBE = 0.7 volt, (Base emitter junction is forward biased) VCB = VBC = 0.2 V (Base to collector junction is reverse biased).

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If for a silicon n-p-n transistor, the base to emitter voltage (V_BE) is 0.7 V and the collector to base voltage V_CB is 0.2 Volt, then the transistor is operating in the

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Electronic Devices and Circuits

If for a silicon n-p-n transistor, the base to emitter voltage (VBE) is 0.7 V and the collector to base voltage VCB is 0.2 Volt, then the transistor is operating in the

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For help Students Orientation Mcqs Questions

If for a silicon n-p-n transistor, the base to emitter voltage (V_BE) is 0.7 V and the collector to base voltage V_CB is 0.2 Volt, then the transistor is operating in the

For help Students Orientation
Mcqs Questions