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Series Circuits - Technical MCQs

Q1:

If four 90 omega.gif resistors are connected in series across an 18 V source, the current equals ___.

A 50 mA

B 0.2 A

C 5 A

D 20 A

ANS:A - 50 mA 

By Ohm's law, V = IR.

I = V/R

Given, Four 90 ohm resisters in series. 

So, R = ( R1 + R2 + R3 + R4) = 4 x 90 = 360 ohms.

Therefore, I = 18/360 = 0.05 A [or] 50 milli amps.