If N = 196, the result of the following program will be INTEGER N, DIGIT 1, DIGIT 2, DIGIT 3, SUMREAD*, NDIGIT 1 = N - (N / 10)* 10 N = N / 10DIGIT 2 = N - (N / 10)* 10 N = N / 10DIGIT 3 = N - (N / 10)* 10SUM = DIGIT 1 + DIGIT 2 + DIGIT 3-A-196B-16C-16.0D-196.0-B-16

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Microprocessors - Engineering

If N = 196, the result of the following program will be `INTEGER N, DIGIT 1, DIGIT 2, DIGIT 3, SUM READ, N DIGIT 1 = N - (N / 10) 10 N = N / 10 DIGIT 2 = N - (N / 10)* 10 N = N / 10 DIGIT 3 = N - (N / 10)* 10 SUM = DIGIT 1 + DIGIT 2 + DIGIT 3`

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Microprocessors - Engineering

If N = 196, the result of the following program will be INTEGER N, DIGIT 1, DIGIT 2, DIGIT 3, SUMREAD*, NDIGIT 1 = N - (N / 10)* 10 N = N / 10DIGIT 2 = N - (N / 10)* 10 N = N / 10DIGIT 3 = N - (N / 10)* 10SUM = DIGIT 1 + DIGIT 2 + DIGIT 3

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If N = 196, the result of the following program will be `INTEGER N, DIGIT 1, DIGIT 2, DIGIT 3, SUM READ, N DIGIT 1 = N - (N / 10) 10 N = N / 10 DIGIT 2 = N - (N / 10)* 10 N = N / 10 DIGIT 3 = N - (N / 10)* 10 SUM = DIGIT 1 + DIGIT 2 + DIGIT 3`

For help Students Orientation
Mcqs Questions