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Numbers

Q1: If n is a natural number, then (6n2 + 6n) is always divisible by:

A 6 only

B 6 and 12 both

C 12 only

D by 18 only

ANS:B - 6 and 12 both

(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.



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