

Numbers - General Aptitude
Q1: If n is a natural number, then (6n2 + 6n) is always divisible by:A
6 only
B
6 and 12 both
C
12 only
D
by 18 only
ANS:B - 6 and 12 both (6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even. |


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