Networks Analysis and Synthesis - Engineering

Q1:

If operator 'a' = 1 ∠120° then (1 - a) =

A
3

B
3 ∠ - 30°

C
3 ∠ + 30°

D
3 ∠60°

ANS:B -

3 ∠ - 30°

1 - a = 1 - 1∠120° = 1 + 0.5 - j 0.866 = 1.5 - j 0.866 = 3∠-30°.