If straight sides of a triangular section of a lined canal with circular bottom of radius R, make an angle θ with horizontal, the area of its cross-section, is-A-R(θ + tan θ)B-R(θ + cot θ)C-R2(θ + tan θ)D-R2(θ + cot θ)E-R(θ + tan θ)-D-R2(θ + cot θ)

Question

If straight sides of a triangular section of a lined canal with circular bottom of radius R, make an angle &theta; with horizontal, the area of its cross-section, is-A-R(&theta; + tan &theta;)B-R(&theta; + cot &theta;)C-R2(&theta; + tan &theta;)D-R2(&theta; + cot &theta;)E-R(&theta; + tan &theta;)-D-R2(&theta; + cot &theta;)

APTITUDE CRACK · Accepted Answer

D R2(&theta; + cot &theta;) The perimeter of the canal is 2R(&Icirc;&cedil; + cos&Icirc;&cedil;).

Irrigation

If straight sides of a triangular section of a lined canal with circular bottom of radius R, make an angle θ with horizontal, the area of its cross-section, is

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Irrigation

If straight sides of a triangular section of a lined canal with circular bottom of radius R, make an angle θ with horizontal, the area of its cross-section, is

Solution

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