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Capacitors

Q1: If the reactive power of a circuit is 50 mW while the apparent power is 64 mW, then what is the true power of the circuit?

A 14 mW

B 36 mW

C 40 mW

D 114 mW

ANS:C - 40 mW

(apparent power)^2=(real power)62+(reactive power)^2 64^2=x^2+50^2 x^2=1596 x=39.999~=40mW



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