Download Aptitude Crack
img not found img not found

Alternating Current and Voltage

Q1:

If the rms current through a 4.7 k resistor is 4 mA, the peak voltage drop across the resistor is

A 4 V

B 18.8 V

C 26.6 V

D 2.66 V

ANS:C - 26.6 V

Im = Irms/0.707.
Vm = Vrms 1.414.

V = IR Vrms = 4*4.7 = 18.8.
Vm = Vrms*1.414.
Vm = 18.8*1.414.

Peak voltage Vm = 26.58.



img not found
img

For help Students Orientation
Mcqs Questions

One stop destination for examination, preparation, recruitment, and more. Specially designed online test to solve all your preparation worries. Go wherever you want to and practice whenever you want, using the online test platform.