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Alternating Current and Voltage - Engineering

Q1:

If the rms current through a 4.7 k resistor is 4 mA, the peak voltage drop across the resistor is

A 4 V

B 18.8 V

C 26.6 V

D 2.66 V

ANS:C - 26.6 V

Im = Irms/0.707.
Vm = Vrms 1.414.

V = IR Vrms = 4*4.7 = 18.8.
Vm = Vrms*1.414.
Vm = 18.8*1.414.

Peak voltage Vm = 26.58.